Difference between revisions of "Ideal Bose Gas"
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In a classical gas, the mean occupation number for a single quantum state satisfies the Boltzmann distribution <math> \langle n_{\nu} \rangle = e^{-(\epsilon_{\nu}-\mu)/kT} </math> which is much less than unity. However, in a condesnate, the occupatyion number in the groud state is much larger than 1. | In a classical gas, the mean occupation number for a single quantum state satisfies the Boltzmann distribution <math> \langle n_{\nu} \rangle = e^{-(\epsilon_{\nu}-\mu)/kT} </math> which is much less than unity. However, in a condesnate, the occupatyion number in the groud state is much larger than 1. | ||
==== Density of States ==== | ==== Density of States ==== | ||
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+ | === Padagogical Example === |
Revision as of 14:32, 3 May 2017
A Bose–Einstein condensate (BEC) is a state of matter of a dilute gas of bosons cooled to temperatures very close to 0K (usually ~100nK in experiments). Under such conditions, a large fraction of bosons occupies the lowest quantum state, at which point macroscopic quantum phenomena become apparent.
Contents
Overview
In this section, we summarize some basic and useful thermodynamic results for Bose-Einstein condensation in a uniform, non-interacting gas of bosons.
Thermodynamics of a Bose Gas
The Bose Distribution
For non-interacting bosons in thermodynamic equilibrium, the mean occupation number of the single-particle state is
In a classical gas, the mean occupation number for a single quantum state satisfies the Boltzmann distribution which is much less than unity. However, in a condesnate, the occupatyion number in the groud state is much larger than 1.